3.5 Shapes of Molecules
Candidates should be able to:
- State and explain the shapes of, and bond angles in, molecules by using VSEPR theory, including CO₂ (linear, 180°), BF₃ (trigonal planar, 120°), CH₄ (tetrahedral, 109.5°), NH₃ (pyramidal, 107°), H₂O (non-linear, 104.5°), PF₅ (trigonal bipyramidal, 120° and 90°) and SF₆ (octahedral, 90°).
- Predict the shapes of, and bond angles in, molecules and ions analogous to those listed above.
1 VSEPR Theory — The Basics ▾
The valence shell electrons are the electrons in the main outer shell of an atom. The shape and bond angles of a covalently bonded molecule depend on:
- the number of pairs of electrons around the central atom, and
- whether those pairs are lone pairs or bonding pairs.
- Pairs of electrons repel each other because they carry the same charge.
- A lone pair repels other pairs more strongly than a bonding pair does.
- Repulsion from a double or triple bond is treated the same as a single bond for working out shape — except that repulsion between two double bonds is greater than between two single bonds.
- The most stable shape is the one that minimises the forces of repulsion between all the electron pairs.
2 Shapes With No Lone Pairs ▾
When every electron pair around the central atom is a bonding pair, the pairs spread out as evenly as possible, giving these three classic shapes:
3 Shapes With Lone Pairs ▾
Ammonia and water both start from the same tetrahedral arrangement of four electron pairs as methane — but one or two of those pairs are lone pairs instead of bonding pairs, which changes the observed shape and squeezes the bond angle.
4 Expanded Octet Shapes ▾
Elements in Period 3 and beyond can accommodate more than 8 electrons around the central atom, giving rise to two further shapes with no lone pairs.
5 Predicting Shapes of Related Molecules & Ions ▾
The same seven reference shapes let you predict the shape of a molecule or ion you haven’t seen before — just work out how many electron pairs surround the central atom, and how many of those are lone pairs.
- Draw the dot-and-cross structure (or count valence electrons) to find the total number of electron pairs around the central atom.
- Identify how many of those pairs are bonding pairs and how many are lone pairs.
- Match this combination to the reference shape with the same number of bonding pairs and lone pairs.
Worked Examples
| Species | Bonding / Lone Pairs | Shape (like…) |
|---|---|---|
| NH₄⁺ | 4 bonding, 0 lone | Tetrahedral, 109.5° (like CH₄) |
| H₃O⁺ | 3 bonding, 1 lone | Pyramidal, ~107° (like NH₃) |
| SO₃ | 3 bonding, 0 lone | Trigonal planar, 120° (like BF₃) |
| PCl₅ | 5 bonding, 0 lone | Trigonal bipyramidal (like PF₅) |
| [SiF₆]²⁻ | 6 bonding, 0 lone | Octahedral, 90° (like SF₆) |
- Count all electron pairs around the central atom first, then classify each as bonding or lone.
- Remember lone pairs repel more strongly, and compress bond angles when present.
- Treat a multiple bond the same as a single bond when counting regions of electron density.
- State both the shape name and the bond angle — both are usually needed for full marks.
- Don’t forget to include lone pairs on the central atom when working out the shape.
- Don’t say NH₃ and CH₄ have the same shape — the extra lone pair makes NH₃ pyramidal, not tetrahedral.
- Don’t give a single “90°” for PF₅ — trigonal bipyramidal has two different bond angles (120° and 90°).
- Don’t confuse the shape of the electron pairs with the shape of the molecule — they’re the same only when there are no lone pairs.
- CO₂: linear, 180° (2 bonding, 0 lone)
- BF₃: trigonal planar, 120° (3 bonding, 0 lone)
- CH₄: tetrahedral, 109.5° (4 bonding, 0 lone)
- NH₃: pyramidal, 107° (3 bonding, 1 lone)
- H₂O: non-linear/bent, 104.5° (2 bonding, 2 lone)
- PF₅: trigonal bipyramidal, 120° and 90° (5 bonding, 0 lone)
- SF₆: octahedral, 90° (6 bonding, 0 lone)